Of Solutions Chapters 6-10

Book Id: WPLBN0000674827
Format Type: PDF eBook
File Size: 449.80 KB
Reproduction Date: 2005

Title:	Of Solutions Chapters 6-10
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Language:	English
Subject:	Science., Mathematics, Logic
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Citation APA MLA Chicago Of Solutions Chapters 6-10. (n.d.). Of Solutions Chapters 6-10. Retrieved from http://gutenberg.us/

Description
Mathematics document containing theorems and formulas.

Excerpt
Excerpt: We have r1 = 2, r2 = 1, r3 = 1 so t1 = 1, t2 = 0, t3 = 1. The algorithm terminates in one step after after subtraction of (X1 +X2 +X3)(X1X2X3). The given polynomial can be expressed as e1e3. We have r1 = 2, r2 = 1, r3 = 0 so t1 = 1, t2 = 1, t3 = 0. At step 1, subtract (X1 +X2 +X3)(X1X2 +X1X3 +X2X3). The result is ?3X1X2X3 +4X1X2X3 = X1X2X3. By inspection (or by a second step of the algorithm), the given polynomial can be expressed as e1e2 + e3.